Any maths geeks out there?

Discussion in 'General Airgun Chat' started by RobF, Dec 20, 2015.

  1. RobF

    RobF Administrator Staff Member

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    Got a question.

    If you have a graph showing acceleration over time, what does the area under the graph represent?
     
  2. john0neuk

    john0neuk Well-Known Member

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    Last edited: Dec 20, 2015
  3. Adam

    Adam Active Member

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    So acceleration is y axis up the side, time is x axis across the bottom, yes?
    I think it would be speed.

    Accel is rate of change of speed. Distance / time^2 = distance / time / time

    If you take the area you multiply the x by the y

    So distance / time / time * time = distance / time which = speed

    Hope that makes sense.
     
  4. Altx

    Altx Member

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    Yes I think you are right, below graph what is achieved and above what is not.
     
  5. bluespots

    bluespots New Member

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  6. eyewitnesss

    eyewitnesss Government Spy

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    eyewitnesss Government Spy

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  8. Tench

    Tench WHFTA World Champion 2016.

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    Surely the axis of the graph would be distance and time?

    I don't think the area under the line represents anything, only the points on the line have any reference to the information?
     
  9. Deleted member 4175

    Deleted member 4175 Non member

    whats a graph :confused:
     
  10. CoolId

    CoolId New Member

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    I've got insufficient blood in my alcohol stream right now. I'll think about it in the morning
     
  11. Nomads HFT

    Nomads HFT Active Member

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    Would the area under the graph represent the average value for acceleration multiplied by the time, and hence the final velocity?
     
  12. rich

    rich Active Member

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    The area under a graph is the product of the X and Y axes.

    So, if acceleration is in units of metres per second ^2, and time is in seconds, multiply seconds by metres per second ^2 and you get metres per second, which is a velocity.

    Why you would want to plot acceleration against time, I don't know.

    Don't forget that anything slowing down exhibits negative acceleration so the plot on your chart will go below the axis.
     
  13. RobF

    RobF Administrator Staff Member

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    We're not plotting it Rich, we're measuring it ;)

    Thanks for the replies. It makes sense... even though the acceleration is considerable, the velocity is small because the duration it acts over is small as well... which reflects observations. We just need to upgrade the measuring stick so there's better detail in the results.
     
  14. AIRFIX GILLY

    AIRFIX GILLY WFTA World Champion 2012

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  15. Welsh Wizard

    Welsh Wizard My Backs Gone! Staff Member

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  16. poison dwarf

    poison dwarf BANNED

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    Wondered what that was that you wrapped around your head :D
     
  17. CoolId

    CoolId New Member

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    Needless to say Rich is the nearest. Actually, using the traditional (when I was a kid) notation

    v = u + a * t

    so

    a * t (the area under the curve) is the accumulated change in velocity (v - u)
     
  18. rich

    rich Active Member

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    No need for modesty, Dave. It needs saying...:)
     
  19. Adam

    Adam Active Member

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    Springer recoil? :D
     
  20. RobF

    RobF Administrator Staff Member

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    Not springer recoil ;)
     

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